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Matematika
iksan148
Pertanyaan
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1 Jawaban
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1. Jawaban AlfandyGulo
[tex] = \frac{( {a}^{4} {b}^{3})^{2} {c}^{ - 2} }{( {a}^{ - 2} {b}^{ - 1} {c}^{ - \frac{2}{3} })^{ - 3} } \\ = \frac{ {a}^{8} {b}^{6} {c}^{ - 2} }{ {a}^{6} {b}^{3} {c}^{2} } \\ = \frac{ {a}^{2} {b}^{3} }{ {c}^{4} }
= \frac{ {2}^{2} \times {3}^{3} }{ {6}^{4} } \\ = \frac{4 \times 27}{1296} \\ = \frac{108}{1296} \\ = \frac{1}{12} [/tex]
Jawaban A