DIKETAHUI M1=4 kg,m2=6kg dan m3=10 kg.Apabila massa katrol diabaikan,tegangan tali T1 dan T2 berturut turut sebesar .......(g=9,8m/s^2)

Diketahui
- Gaya gesek = 0 (diabaikan)
- M1 = 4 kg
- M2 = 6 kg
- M3 = 10 kg
- g = 9,8 m/s²

Ditanya
- T1 = ....?
- T2 = .....?

Penyelesaian

- Mencari percepatan
[tex]a = \frac{m3.g - \psi \: k.n1 - \psi \: k.n2}{m1 + m2 + m3} \\ a = \frac{10 \times 9.8 - 0 \times n1 - 0 \times n2}{4 + 6 + 10} \\ a = \frac{98 - 0 - 0}{20} \\ a = \frac{98}{20} \\ a = 4.9 \: m \: s[/tex]
- Tegang tali 1 (T1)

[tex]f = m1 \times a \\ t1 = 4 \times 4.9 = 19.6 \: n[/tex]

- Tegang tali 2 (T2)

EF3 = m3 x a
W3 - T3 = m3 x a
m3 . g - T2 = m3 x a
T2 = 10 x 9,8 - 10 x 4,9
T2 = 49 N