tolong jwb ya makasih

3.<DCE = 110°
a) <BCD = 180° - 110° (berpelurus)
<BCD = 70°
b)<BAD = 1/2 <BPD luar(sudut bantuan)
<BPDluar = 360° - (2 x <BCD)
<BPDluar = 360° - (2 x 70°)
<BPDluar = 360° - 140°
<BPDluar = 220°
<BAD = 1/2 x 220°
<BAD = 110°
c) <ABD = 180° - <BAD
———————
2
(karena AB = AD)
<ABD = 180° - 140°
——————
2
<ABD = 20°

5.<AOC = 80°
a) <ABC = 1/2 <AOC luar
<ABC = 1/2 (360 - 80)°
<ABC = 1/2 x 280°
<ABC = 140°
b)<BAO + <BOC =
360° - ( <ABC + <AOC )
<BAO + <BOC = 360° - (140 + 80)°
<BAO + <BOC = 360° - 220°
<BAO + <BOC = 140°
Semoga membantu :)