1/(akar 3 - akar 2)pangkat 2 bantu kak,please

1/(√3-√2)²
= 1/(√3-√2)(√3-√2)
= 1/3-√12+2
= 1/5-√12
= 1/5-2√3

1/(√3-√2)² = 1/(3-2√6 + 2) = 1/(5-2√6) x (5+2√6)/(5+2√6) = (5+2√6)/(25-24) = 5+2√6
Semoga membantu.