Matematika

Pertanyaan

berapakah nilai dari 1 kuadrat - 2 kuadrat + 3 kuadrat - 4 kuadrat + 5 kuadrat - 6 kuadrat + ...+ 2017 kuadrat ?

1 Jawaban

  • 1² - 2² + 3² - 4² + 5² - 6² + ... + 2017²

    = 1² + (-2² + 3²) + (-4² + 5²) + ... + (-2016² + 2017²)

    = 1 + ((3 - 2) . (3 + 2)) + ((5 - 4) . (5 + 4)) + ... + ((2017 - 2016) . (2017 + 2016))

    = 1 + 5 + 9 + ... + 4033


    a = 1

    b = 4


    Un = 4.033

    a + (n - 1) . b = 4.033

    1 + (n - 1) . 4 = 4.033

    (n - 1) . 4 = 4.033 - 1

    n - 1 = 4032/4

    n = 1.008 + 1

    n = 1.009


    Sn = n/2 . (a + Un)

    S1009 = 1.009/2 . (1 + 4033)

    S1009 = 1.009/2 . 4.034

    S1009 = 2.035.153


    Kelas 9

    Pelajaran Matematika

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