diketahui f ( X ) = 3x²- 2x - 1 dan g ( X ) = [tex] \sqrt{x} - 3.nilai {f o g }{ 16 }[/tex] =

f(x)=3x^2-2x-1
g(x)=√x-3

fog(x)=3(√x-3)^2-2(√x-3)-1
=3(x-6√x+9)-2√x-6-1
=3x-18√x+27-2√x-7
=3x-20√x+20

fog(16)=3(16)-20(√16)+20
=48-20(4)+20
=68-80
=-12

f(x) = 3x² - 2x - 1
g(x) = √x - 3

(f o g)(16)
= f(g(16)) ==> g(16) = √16 - 3 = 4 - 3 = 1
= f(1)
= 3(1)² - 2(1) - 1
= 3 - 2 - 1
= 0