tolong dijawab yaaaaaaaa

1 + 1 / {2 + [1 / (3 + 1/×)]}
selesaikan dari kurung paling dalam.

(3 + 1/×)
3 + 1/x = 3/1 + 1/x = (3x + 1)/x.

[1 / (3x+1)/x]
= 1/1 x x/(3x+1)
= x/(3x+1)

2 + [x/(3x+1)]
= [x/(3x+1) + (6x+2)/(3x+1)]
= (7x+2) / (3x+1)

1 / [(7x+2) / (3x+1)]
= 1/1 × (3x+1) / (7x+2)
= (3x+1) / (7x+2)

1 + [(3x+1) / (7x+2)]
= [(7x+2) / (7x+2)] + [(3x+1) / (7x+2)]
= (10x+3) / (7x+2)