diketahui suatu persegi panjang dengan panjang (3x + 5) cm dan lebar (2x - 2) cm.jika keliling persegi panjang tersebut 56 cm,maka panjang dan lebar persegi pan

- Bangun Datar -

P = 3x+5 cm
L = 2x-2 cm

K = 56 cm
2p + 2l = 56
2(3x+5) + 2(2x-2) = 56
6x+10+4x-4 = 56
10x+6 = 56
10x = 50
x = 5

Maka
P = 3x+5
P = 3(5) + 5 = 15 + 5 = 20 cm

L = 2x-2
L = 2(5) -2 = 10-2 = 8 cm

Jawaban : D
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panjang = 3x + 5
lebar = 2x - 2

keliling = 2(p + l)
56 = 2(3x + 5 + 2x - 2)
56 = 2(5x + 3)
28 = 5x + 3
25 = 5x
x = 5

panjang = 3(5) + 5 = 15 + 5 = 20
lebar = 2(5) - 2 = 10 - 2 = 8

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