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Larutan basa lemah LOH 10-6 M (Kb = 4 x 10-4) mempunyai pH …

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  • M = 10^-6 M
    Kb = 4 X 10^-4
    pH = ....?

    [OH-] = √Kb . M = √4 X 10^-4 . 10^-6 M = √4 X 10^-10 = 2 X 10^5

    pOH = - log [OH-] = - log 2 X 10^-5 = 5 - log 2 = 5 - 0,301 = 4,69897 = 4,7

    pH = 12 - 4,7 = 7,3


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