Matematika

Pertanyaan

dik α+β=π/3 dan sinαsinβ=1/4 nilai dari cos (α-β)=

2 Jawaban

  • cos (α-β) = cosαcosβ + sinαsinβ
    = cosαcosβ + ¼

    cos (α+β) = cosαcosβ - sinαsinβ
    cos π/3 = cosαcosβ - ¼
    ½ = cosαcosβ - ¼
    ¾ = cosαcosβ

    cos (α-β) = cosαcosβ + sinαsinβ
    = cosαcosβ + ¼
    = ¾ + ¼
    = 1 ✔️

    semoga jelas dan membantu
  • sin a sin b = 1/4
    sin a sin b = 1/2 (cos (a-b)) - 1/2(cos(a+b))
    1/4 = 1/2 (cos(a-b)) - 1/2 (cos (π/3))
    1/4 = 1/2 (cos(a-b)) - 1/2 (1/2)
    1/4 = 1/2 (cos(a-b)) - 1/4
    1/4 + 1/4 = 1/2 (cos(a-b))
    1/2 = 1/2 (cos(a-b))
    cos(a-b) = 1

    semoga benar dan bermanfaat

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