pada kubus ABCD.EFGH disamping.panjang rusuk AB=12cm. a.panjang CH b.luas ABCH

AB = BC = CD = DA = EF = FG = GH = HE = AE = BF = CG = DH = 12 cm

A. Panjang CH
= √CG² + GH²
= √12² + 12²
= √288
= 12√2 cm

B. Luas ABCH
= panjang AB x Panjang CH
= 12 x 12√2
= 144√2 cm²