hitunglah larutan CH3COOH 0,125M dengan Ka=2.10^-6

pH larutan =


[H+] = akar (Ka. Ma)
= akar 2. 10^-6 x 0.125
= akar 2.5 x 10^-6
[H+] = 5 x 10^2.5

pH = -Log [H+]

pH = - log 5 x 10^2.5
pH = 2.5 - log 5
pH = 2.5 - 0.7
pH = 1.8