Matematika

Pertanyaan

Tolong yaa soal nomer 1 sampek 5
Tolong yaa soal nomer 1 sampek 5

1 Jawaban

  • 1).u=AB
    AB=B-A
    =(-3,10,-14) - (3,1,-2)
    =(-6,9,-12)
    v=AC
    AC=C-A
    =(1,2,1)-(3,1,-2)
    = (-2,1,3)
    1/3u + 2v
    =1/3(-6,9,12) + 2(-2,1,3)
    =(-2,3,4) + (-4,2,6)
    =(-6,5,10)

    2).caranya sama seperti no 1

    3).a= (3,-2p,-1), b =(p, 6,3) ,c (-5,4q,2)
    jika a + b = c
    =(3,-2p,-1) + (p, 6,3) = (-5,4q,2)
    =(3+p , -2p+6 , 2) = (-5 ,4q , 2)
    3+p = -5
    p = -8
    -2p+6 = 4q
    -2(-8)+6 = 4q
    16 + 6 = 4q
    22 = 4q
    22/4=q
    11/2 = q

    maaf ya cuma itu :)
    koreksi lagi ya...