nilai dari √108 + √75 - √432

[tex] = \sqrt{108} + \sqrt{75} - \sqrt{432} \\ = \sqrt{36 \times 3} + \sqrt{25 \times 3} - \sqrt{144 \times 3} \\ = 6 \sqrt{3} + 5 \sqrt{3} - 12 \sqrt{3} \\ = (6 + 5 - 12) \sqrt{3} \\ = - 1 \sqrt{3} \\ = - \sqrt{3} [/tex]
Semoga membantu☑

6√3 + 5√3 - 12√3
11√3 - 12 √3
-1√3
-√3

maaf klo slh