Hasil dari integral 18x(1-2x)pangkat 5 dx adalah...

18x(1-2x)^5dx = 18x(dx-32.d.2x)
=(18).(32).(2)x^1+1+1 d^1+1
= (6.3)×(8.4)×(2).x^3.d^2
=(2.3.3)×(2^3.2^2)×(2).x^3.d^2
=(2^1+3+2+1)×(3^1+1).x^3. d^2
=2^7×3^2.x^3.d^2
2^7/3^2=x^3.d^2


semoga membantu

Int 18x (1-2x)^5 dx

Mis : u = 1-2x ---> du = -2 dx
dx = - du/2
2x = 1-u
x = 1-u / 2

= Int 18(1-u /2).u^5 (-du/2)
= - int 9/2 (1-u) u^5
= -9/2 int (1-u) u^5 du
= -9/2 int u^5 - u^6 du
= -9/2 . (¹/6 u^6 - ¹/7 u^7) +c
= -³/4 u^6 + 9/14 u^7 + c
= -³/4 (1-2x)^6 + 9/14 (1-2x)^7 + c