Hitunglah pH larutan 300ml larutan KOH 0,1M

[ans]

KOH ⇒ K⁺ + OH⁻

Valensi basa (x) adalah 1. Jika diketahui volume (v) 300 ml dan konsentrasi (M) adalah 0.1 M, maka pH larutan adalah:

[tex] \left[\text{OH}^{-}\right]=x\cdot\text{M}\\\\ \left[\text{OH}^{-}\right]=1\cdot 0.1\\\\ \left[\text{OH}^{-}\right]=0.1 \rightarrow 10^{-1}\\ \rule{4cm}{1pt}\\\\ \text{pOH}=-\log{\left[\text{OH}^{-}\right]} \\\\ \text{pOH}=-\log{10^{-1}} \\\\ \text{pOH}=1\\ \rule{4cm}{1pt}\\\\ \text{pH}=\text{k}_W-\text{pOH}\\\\ \text{pH}=14-1\\\\ \text{pH}=\bf13[/tex]