Luas bangun diatas adalah A. 100cm² B. 150cm² C. 200cm² D. 300cm²

Penyelesaian :
Tinggi segitiga
[tex] = \sqrt[2]{ {20}^{2} - {16}^{2} } \\ = \sqrt[2]{400 -256 } \\ = \sqrt[2]{144} = 12 \: \: cm[/tex]

Luas segitiga
= 1/2 × a × t
= 1/2 × 9 cm × 12 cm
= 54 cm²

Luas segitiga
= 1/2 × a × t
= 1/2 × 16 cm × 12 cm
= 96 cm²

Luas gabungan
= 54 cm² + 96 cm²
= 150 cm²
Opsi => B

Good Luck :)

t² = 20²- 16²
t²= 400- 256
t² = 144
t= √144
t = 12cm

alas = 16+ 9
= 25cm

Lsegitiga = 1/2 x alas x tinggi
= 1/2 x 25cm x 12cm
= 25cm x 6 cm
= 150cm²(B)