Tolong bantu jawab dong..

v4 / v3 = {k [A]^x [B]^y} / {k [A]^x [B]^y}
1,6 × 10^-3 / 0,8 × 10^-3 = {[0,04]^x [0,8]^y} / {[0,04]^x [0,4]^y}
2 = 2^y
y = 1.

v2 / v1 = {k [A]^x [B]^y} / {k [A]^x [B]^y}
3 × 10^-4 / 0,5 × 10^-4 = {[0,02]^x [0,3]^y} / {[0,01]^x [0,1]^y}
6 = 2^x × 3^y
6 = 2^x × 3^1
6 = 2^x × 3
2^x = 2
x = 1.

jadi persamaan laju reaksi :
v = k [A]^x [B]^y
= k [A] [B]