jika g(x-2) = 2x-3 dan (f·g)(x-2) = 4x²-8x+3 maka f(-3) adalah?

(f o g)(x - 2) = 4x^2 - 8x + 3
f(g(x - 2)) = 4x^2 - 8x + 3
f(2x - 3) = 4x^2 - 8x + 3

Jika 2x - 3 = y
Maka x = (y + 3)/2

[tex]f(y) = 4( \frac{y + 3}{2})^{2} - 8( \frac{y + 3}{2} ) + 3 \\ f(y) = 2( {y}^{2} + 6y + 9) - 4(y + 3) + 3 \\ f(y) = 2 {y}^{2} + 12y + 18 - 4y - 12 + 3 \\ f(y) = 2 {y}^{2} + 8y + 6 + 3 \\ f( - 3) = 2( { - 3})^{2} + 8( - 3) + 6 + 3\\ f (- 3) = 18 - 24 + 6 + 3\\ f( -3 ) = 3[/tex]