nilai ³log1/9+³log 4. 16log 9 adalah tolong bantu sy..mau di anter besok ini ..

[tex]^{3} log \: \frac{1}{9 } + ^{3} log \: 4. ^{16} log \: 9 \\ = ^{3} log \: \frac {1}{9 } + ^{3} log \: {2}^{2} \: . \: ^{ {2}^{4} } log {3}^{2} \\ = ^{3} log \: {3}^{ - 2} + 2 \times \frac{2}{4} \times \: ^{3} log \: {3}^{2} \\ = ^{3} log \: {3}^{ - 2} + ^{3} log \: {3}^{2} \\ = - 2 \times 2 \\ = - 4[/tex]