tolong banget ya, sekalian pakai cara

7. A.........
8. C.....................

7. A, <ACB = sudut keliling = [tex] \frac{1} {2} [/tex] <AOB = [tex] \frac{1} {2} [/tex].70=35
8.  A. <KML = sudut keliling = [tex] \frac{1} {2} [/tex] <KOL
KOL=180-<KON=180-100=80
<KML=[tex] \frac{1} {2} [/tex].80 = 40