tolong ya cara ny jg!!

itu jawabannya
semoga bermanfa'at dan paham yaa

[4log9 . √27log(1/125) . 5log√8]
/ [4log32 - 2log16]

= [(2^2)log(3^2) . (3^3/2)log(5^-3) . 5log(2^3/2)] / [(2^2)log(2^5) - 2log(2^4)]

= [(2/2) . 2log3 . -3/(3/2) . 3log5 . 3/2 . 5log2] / [5/2 . 2log2 - 4 . 2log2]

= [1 . -2 . 3/2 . 2log3 . 3log5 . 5log2] / [5/2 . 1 - 4 . 1]

= [-3 . 2log2] / [5/2 - 4]

= [-3] / [-3/2]

= 2

^ = pangkat