tolong ya jawab soal tentang fungsi invers. besok dikumpul

1.a.
(fog)(x) = f(g(x))
= f (2x+1)
= 4(2x+1) -2
= 8x + 4 - 2
= 8x + 2
a = 8 ,b= 2

[tex] f^{-1} = \frac{x-b}{a} [/tex]

 f^-1 = x - 2 / 8

1.b.
(gof)(x)=g(f(x))
=g (4x-2)
=2(4x-2)+1
= 8x - 4 +1
= 8x - 3
a=8, b= -3
f^-1 = x-b/a
=x - (-3)/8
= x + 3 / 8

2.a.
fog(x) = f(g(x))
=f(3x+1)
=6(3x+1)+ 1 / 3(3x+1) -1
=18x + 6 + 1 / 9x + 3 -1
= 18x + 7 / 9x + 2

a=18,b=7,c=9,d=2

[tex] f^{-1} = \frac{-dx+b}{cx-a} [/tex]

 f^-1 = -2x + 7 / 9x - 18

2.b. sama kayak yg a ya..


maaf kalau salah :)
koreksi lagi ya...