²Log (x-6) < 1 tolong jawab yaaa yg bisa

[tex] ^{2}Log(x-6) < 1 \\ ^{2}Log(x-6) < ^{2}Log 2[/tex]
karena log nya sama maka bisa dihilangkan 
menjadi [tex]( x - 6) < 2 \\ x - 6 < 2 \\ x < 2 + 6 \\ x < 8[/tex]

[tex]^{4}Log( x^{2} + 4x + 4) < 2 \\ ^{4}Log( x^{2} + 4x + 4) < ^{4}Log( 16) \\ x^{2} + 4x + 4 < 16 \\ ( x + 2 )^{2} < 4^{2} \\ x + 2 < 4 \\ x < 2[/tex]