Diket f(3x+1)=9x -2 dan (f o g) (x)=-6x² +16. Nilai g(3)= …?
Matematika
ifahazizahh
Pertanyaan
Diket f(3x+1)=9x -2 dan (f o g) (x)=-6x² +16. Nilai g(3)= …?
1 Jawaban
-
1. Jawaban ardie34454
Invers f(x)=9 (x-1/3)-2= 3x-5
Di masuk ke invers g(3x-5)=-6(x+5/3)^2+16
= -2(x+5)^2+16
=-2 (×^2+10x+25)+16=-2x^2-20x-50+16
g (3)=-2(3)^2-20 (3)-34
=-18-60-34=-112